Typescript type T is not assignable to type T&U in anonymous function

I have an issue where type (text: string) => void is not assignable to type intersection ((text: string) => void) & (() => any) & ...

My code looks as follows:

import React, { Component } from 'react';import { SearchBar } from 'react-native-elements';export default class SearchBarComponent extends Component {    state = {        search: '',    }    updateSearch = (search: string) => {        this.state = { search };    };    render(){        return(<div><SearchBar                    platform="default"                    round                    onChangeText={(text) => (this.updateSearch(text))}                    placeholder="Search..."                    value={this.state.search}                /></div>        )    }}

And my error message states:

Type error: Type '(text: string) => void' is not assignable to type '((text: string) => void) & ((text: string) => void) & (() => any) & (() => any) & (() => any) & ((text: string) => void) & (() => any) & (() => any) & (() => any)'.  Type '(text: string) => void' is not assignable to type '() => any'.  18 |                     platform="default"  19 |                     round> 20 |                     onChangeText={(text) => (this.updateSearch(text))}     |                     ^  21 |                     placeholder="Search..."  22 |                     value={this.state.search}  23 |                 />

I suspect that I need to do type assertion as in https://www.tutorialsteacher.com/typescript/type-assertion, but I cannot quite figure it out. How do I do type assertion on anonymous functions?